(21(x - y) = 48 + 20x,19(y + x) = 100 + 12y.методом - вопрос №125789432148201910012 от 3523512 15.02.2020 11:45

Question

Математика: (21(x - y) = 48 + 20x,19(y + x) = 100 + 12y.методом постановки заранее

3523512 · Answer

[tex]rac{m^2-25}{m^2+10m+25} =rac{(m-5)(m+5)}{(m+5)^2}=rac{m-5}{m+5}[/tex][tex]rac{m^2+10m+25}{25-m^2} =rac{(m+5)^2}{(5-m)(5+m)}=rac{m+5}{5-m}[/tex][tex]rac{m^2-10m+25}{m^2-25}=rac{(m-5)^2}{(m-5)(m+5)}=rac{m-5}{m+5}[/tex][tex]rac{25-m^2}{m^2-10+25}=rac{m+5}{m-5}[/tex]5.[tex]rac{5(a-5)}{a^2-25}=rac{5}{a+5}[/tex]при a=-4,5 [tex]rac{5}{a+5}= rac{5}{0,5}= 10[/tex][tex]rac{9a^2-6+1}{6a-2} = rac{9 a^{2} - 5}{6 a - 2}=rac{3 a}{2} + rac{1}{2} - rac{2}{3 a - 1}[/tex]при...