2х – 3 1; 3 – 8х ≤ 1; 3(2х + 1) – 6 2 – 3(1 – 3х); - вопрос №122215372313813216231382 от kirasanovnagmailcom 08.05.2022 02:40

Question

Математика: 2х – 3 1; 3 – 8х ≤ 1; 3(2х + 1) – 6 2 – 3(1 – 3х); – (8х – 2) – 2(х – 3) ≥ 0.

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2х – 3 >1; 3 – 8х ≤ 1; 3(2х + 1) – 6 < 2 – 3(1 – 3х); – (8х – 2) – 2(х – 3) ≥ 0.

2х – 3 >1;
3 – 8х ≤ 1;
3(2х + 1) – 6 < 2 – 3(1 – 3х);
– (8х – 2) – 2(х – 3) ≥ 0.