Площини рівнобедрених трикутників АВС і АВД з основами АВ перпендикулярні.Знайти відстань між їх вершинами С і Д якщо АВ=5см,АС=6 см,АД=8 см

Так  смотри:   (х-14,4) -  5/12.  =  значит  в  начале  переводим  14,4  =14     4/10 затем  наоборот  (я  решаю  как  наприер  цифры  поменяй  :   х-4                        14,4 -  2 5/12  -  2 значит  2  +2  +  4  (4  -  х)) значит:   14      4/10  +  5/12 =  14      1/60 затем:   14      1/60  +  5/12 =  считай: )

Пошаговое объяснение:

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