ответ: x₁=-π/4 x₂=5π/4.
Пошаговое объяснение:
2*sin(3x+π/3)=√2 |÷2
sin(3x+π/3)=√2/2
1) sin(3x+π/3)=sin(π/4)
3x+π/3=π/4
3x=π/4-π/3
3x=(3π-4π)/12
3x=-π/12 |÷3
x₁=-π/36.
2) sin(3x+π/3)=sin(3π/4)
3x+π/3=3π/4
3x=3π/4-π/3
3x=(3π*3-4π)/12
3x=(9π-4π)/12
3x=5π/12 |÷3
x₂=5π/36.
