log(a) bc = log(a) b + log(a) c
log(3) a = -5
log(3) 27a = log(3) 27 + log(3) a = log(3) 3³ + log(3) a = 3 - 5 = -2
-2
Пошаговое объяснение:
log3(27a)=log3(3^3*3^-5)=log3(3^-2)=-2
log3a=-5 => 3^-5=a
