Сім'я Кирила Тура (з твору Чорна Рада)​

1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}1+\frac{x+1}{3}=x-\frac{3x+1}{8}