n(NaCl3)=0.01моль
n=m÷M n=V÷Vm n=N÷Na
M(NaCl3)=23+35.5×2=94
m(NaCl3)=n(NaCl3)×M(NaCl3)=94×0.01=0.94г
V(NaCl3)=n(NaCl3)×Vm=0.01×22.4=0.224 л
N(NaCl3)=n(NaCl3)×Na=0.01×6.02×10^23=
=6.02×10^21
