9класс. w(c)-80% w(h)-20% d(,875 молекулярнаяя формула вуглеводню-?

Дано

w(C) = 80% = 0.8

w(H) = 20% = 0.2

D(CH4) = 1.875

CxHy

Решение

D(CH4) = Mr(CxHy) / Mr(CH4) = Mr(CxHy) / (12 * 4 + 1) = Mr(CxHy) / 16 = 1.875

Mr(CxHy) / 16 = 1.875

Mr(CxHy) = 30

x = (Mr(CxHy)w(C)) / Ar(C) = (30 * 0.8) / 12 = 24 / 12 = 2

y = (Mr(CxHy)w(H)) / Ar(H) = (30 * 0.2) / 1 = 6 / 1 = 6

ответ: C2H6