дано
m(Zn) = 6.5 g
m(ZnCL2)-?
Zn+2HCL-->ZnCL2+H2
M(Zn) = 65 g/mol
n(Zn) = m/M = 6.5 / 65 = 0.1 mol
n(Zn) = n(ZnCL2) = 0.1 mol
M(ZnCL2) = 136 g/mol
m(ZnCL2) = n*M = 0.1 * 136 = 13.6 g
ответ 13.6 г
