How many grams nitric acid can be obtained from 2 mol ammoniac

Have:
n(NH₃) - 2 mol
To find: m(HNO₃)
Solve:
The ratio of ammonia to nitric acid is 1:1
NH₃ → HNO₃

n(HNO₃) = 2 mol
m(HNO₃) = n(HNO₃) · M(HNO₃) = 2 · (1+14+16·3) = 2 · 63 = 126 g/mol
Answer: m(HNO₃) = 126 g/mol