дано
m(Na) = 2.3 g
V(H2)-?
2Na+2HCL-->2NaCL+H2
M(Na) =23 g/mol
n(Na) = m/M = 2.3 / 23 = 0.1 mol
2n(Na) = n(H2)
n(H2) = 0.1 / 2 = 0.05 mol
V(H2) = Vm * n = 22.4 * 0.05 = 1.12 L
ответ 1.12 л
