ррр322
05.11.2022 20:38

Task1. Read the short texts about fantasy creatures. There are lots of stories about fantasy animals. Sometimes the animals were strong and killed people; sometimes they were signs of good luck. Here is some information about six famous fantasy animals.
Unicorns were beautiful creatures like horses. They had a long pointed horn in the middle of their foreheads. The horn was magical. If a unicorn put its horn in dirty water, the water became clean. Unicorns were a sign of good luck, but only honest people could see them.
Centaurs were wild creatures. They were half-man, half-horse. They lived a long time ago in Greece. Most centaurs were soldiers but one centaur was different. His name was Chiron. He was a famous teacher. When he died he changed into a star called Sagittarius.
The Minotaur was a very scary creature. It had a bull’s head and a man’s body. It lived in a labyrinth on an island called Crete. If anybody went into the labyrinth, they got lost and could never get out again. Every year, people from the island of Minos sent 7 boys and girls into the labyrinth. The Minotaur ate them.
One year, a brave man called Theseus killed the Minotaur. He took a ball of string from a princess and used it to go in and out of the labyrinth.
Chinese dragons were good, friendly and intelligent. They were made from the parts of nine animals: a snake’s body, a fish’s scales, a clam’s stomach, a tiger’s feet, an eagle’s claws, a camel’s face, a deer’s antlers, a cow’s ears and golden eyes.
Griffins were very strong creatures. They had a lion’s body and an eagle’s head and wings. They could fly. They were the kings of all the animals and birds. They lived in the mountains. Their nests were made of gold. They didn’t lay eggs, they laid sapphires.
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Task1. Read the short texts about fantasy creatures. There are lots of stories about fantasy animals

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Ответ:
anya64yankop08swl
05.04.2022 17:21

№1

SO₂ M(S)=32   M(0)=16 M(SO₂)=32+16*2=64

a)W(S)=32/64*100%=50%

b)M(SO3)=32+16*3=80

80>64

c)W(S)=32/80*100%=40% W(O)=16*3/80=48/80=60%

№2

a)SixOy W(Si)=46,7%=0,467

M(Si)=28 M(O)=16 M(SixOy)=28/0,467=60

60/28=2,1

60/16=3,75(округлим)

Si:O=2:4=1:2

SiO₂

b)M(SiO2)=28+16*2=60

№3

a)2Mg+O₂=2MgO

b)6Na+N₂=2Na₃N

c)2Al+3S=Al₂S₃

№4

a)В результате реакции молекулы метана с двумя молекулами кислорода образовалось две молекулы воды и одна молекула углекислого газа.

b)CH₄+2O₂=CO₂+2H₂O

№5

а)3MgO+2H₃PO₄=Mg₃(PO₄)₂+3H₂O Реакция обмена

b)2Al+3H₂SO₄=Al₂(SO₄)₃+3H₂ Реакция замещения

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Ответ:
sashafedorishyn
10.07.2020 22:27

Ну уравнение в начале:

2H2 + O2 = 2H2O + 484 кДж

1) По уравнению реакции, горит 2 моль водорода, найдем массу этих двух моль водорода:

m=n*M=2моль*2г/моль=4грамма

2) Раасчитаем массу 5 моль водорода:

5моль*2г/моль = 10 грамма

3) Составим пропорцию:

4 грамма -> 484 кДж

10 грамм -> х кДж

Решаем эту пропорцию и получаем:

х = 1210

P.S. человеку решившему ниже. Если вы копируете мое решение, будтье добры, хотя бы на условие внимательно глядеть, ибо у нас тут не 2,24литра как в задаче от 27.11.2012, а 5моль, так что вот...

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