CaCO3+2HCl=CaCl2+CO2+H2O
m(CaCO3)=60-60*8\100=55.2 gr
n(CaCO3)=55.2\100=0.552 mol
n(CaCO3)=n(CO2)=0.552 mol
V(CO2)=Vm*n=0.552*22.4=12.3648л
