Толуол- (+cl2) получили x1 - c6h5coh - (+k2cr2o7+h2so4) - вопрос №15542182165227242 от AsuWi 22.04.2021 10:41

Question

Химия: Толуол- (+cl2) получили x1 - c6h5coh - (+k2cr2o7+h2so4) x2 - (+c2h5oh) x3

AsuWi · Answer

C6H5-CH3+Cl2(t) = C6H5-CH2Cl+HCl C6H5-CH2Cl+KOH=C6H5-CH2OH+KCl C6H5-CH2OH+CuO(t) =C6H5-COH+Cu+H2O 3C6H5-COH+K2Cr2O7+4H2SO4= 3C6H5-COOH+K2SO4+Cr2(SO4)3+4H2O C6H5-COOH+C2H5OH= C6H5-CO-O-C2H5 +H2O...

Толуол-> (+cl2) получили x1 -> c6h5coh -> (+k2cr2o7+h2so4) x2 -> (+c2h5oh) x3