M = 8.625 * 16 = 138 г/моль
CO2 ==> C
56.049/22.4 = x/12
x = 30.02625 г
H2O ==> 2H
40.54/18 = y/2
y = 4.5 г
30.02625 + 4.5 = 34.52625 ≈ 34.53 г
CxHy
12x = 30.02625
y = 4.5
x = 2.5
x = 10
y = 18
C10H18 декил.
