дано
m(C2H2) = 48 g
V(O2) - ?
2C2H2+5O2-->4CO2+2H2O
M(C2H2) = 26 g/mol
n(C2H2) = m/M = 48 / 26 = 1.85 mol
2n(C2H2) = 5n(O2)
n(O2) = 1.85*5 / 2 = 4.625 mol
V(O2) = n*Vm = 4.624 *22.4 = 103.6 L
ответ 103.6 л
Объяснение:
