дано
m(Cu) = 160 g
V(SO2)-?
Cu+2H2SO4(k)-->CuSO4+SO2+2H2O
M(Cu) = 64 g/mol
n(Cu) = m/M = 160 / 64 = 2.5 mol
n(Cu) = n(SO2) = 2.5 mol
V(SO2) = n*Vm = 2.5 * 22.4 = 56 L
ответ 56 л
Объяснение:
