1)
дано
V(H2) = 33.6 L
m(CH4)- ?
C+2H2-->CH4
n(H2) = v/Vm = 33.6 / 22.4 = 1.5 mol
2n(H2) = n(CH4)
n(CH4) = 1.5 / 2 = 0.75 mol
M(CH4) = 16 g/mol
m(CH4) = n*M = 0.75* 16 = 12 g
ответ 12 г
2.
дано
m(ppa HCL) = 73 g
W(HCL) = 20 %
V(H2)-?
m(HCL) = 73 * 20% / 100% = 14.6 g
Mg+2HCL-->MgCL2+H2
M(HCL) = 36.5 g/mol
n(HCL) = m/M = 14.6 / 36.5 = 0.4 mol
2n(HCL) = n(H2)
n(H2) = 0.4 / 2 = 0.2 mol
V(H2) = n*Vm = 0.2 * 22.4 = 4.48 L
ответ 4.48 л
Объяснение:
