дано
m(H2SO4) = 98 g
V(H2)-?
2К+H2SO4-->K2SO4+H2
M(H2SO4) = 98 g/mol
n(H2SO4) = m/M = 98 / 98 = 1 mol
n(H2SO4) = n(H2) = 1 mol
V(H2) =Vm*n = 22.4 * 1 = 22.4 L
ответ 22.4 л
Объяснение:
