M(p) = 2.09*44 = 92 г/моль
CO2 ==> C
7.7/44 = x/12
x = 2.1 г
H2O ==> 2H
1.8/18 = y/2
y = 0.2 г
2.1 + 0.2 = 2.3 (г);
2.3 = 2.3 ==> О не было.
CxHy
12x = 2.1
y = 0.2
x = 0.175 x40
y = 0.2 x40
x = 7
y = 8
C7H8 — толуен.
