дано
m(H2O) = 17 g
V(H2)-?
2Rb+2HOH-->2RbOH+H2
M(H2O) = 18 g/mol
n(H2O) = m/M = 17 / 18 = 0.94 mol
2n(H2O) = n(H2)
n(H2) = 0.94 / 2 = 0.47 mol
V(H2) = n*Vm = 0.47 * 22.4 = 21.056 L
ответ 21.056 л
Объяснение:
