Понятно: ∫2(√(3x+5) dxЗамена t = 3x+5; dt = 3 dx; dx = dt/3;После замены: ∫(2/3) *√t * dt = (2/3) * (2/3) * t^(3/2) = (4/9) * (3x+5)^(3/2) + C
