Choose the most appropriate type of printer for these situations from the descriptions in B opposite. 1 a home user who wants to print text documents and family photographs

2 business people who need to print in large quantities at high quality in an office

3 engineers who want to make detailed line drawings

4 professional typesetters in desktop publishing (e.g. to publish catalogues and magazines)

5 a company that wants to print carbon copies of bills and receipts

Find terms in B opposite which correspond to these definitions.

1 a container that holds the ink in an ink-jet printer

2 powdered ink used in laser printers

3 small needles that press on the inked ribbon to make the characters on paper

4 printer technology that produces text and pictures by hammering pins against a ribbon and the paper

5 a language that tells a printer how to print a document

6 a peripheral which combines a printer, a fax machine and photocopying and scanning capability into one device

​

На C++

#include <iostream>
using std::cout;

using std::cin;
using std::endl;
#include <cstdlib>
using std::rand;
using std::srand;
#include <ctime>
using std::time;

int main()
{
   int B[4][5];
   int sum[5] = { 0 };
   long product = 1;

   srand(time(0));

   //Инициализировать массива значениями от 0 до 9 и вывести таблицу на экран
   for(int i = 0; i < 4; i++)
   {
      for(int j = 0; j < 5; j++)
      {
         B[i][j] = rand() % 10;
         cout << B[i][j] << ' ';
      }
      cout << endl;
   }
   cout << endl;

   //Записать в одномерный массив сумму эллементов столбца
   for(int i = 0; i < 5; i++)
   {
      for(int j = 0; j < 4; j++)
      {
         sum[i] += B[j][i];
      }
   }

   //Вывести на экран значения одномерного массива
   for(int i = 0; i < 5; i++)
   {
      cout << sum[i] << ' ';
   }
   
   //Вычесление произведения(умножения)
   for(int i = 0; i < 5; i++)
   {
      product *= sum[i];
   }

   cout << "\n\nProduct = " << product << endl;

   cin.get();
   return 0;
}

(1) A
(2) AAB
(3) AABAABC
(4) AABAABCAABAABCD
(5)
(6)
(7)
(8)


AABAABCAABAABCDEFGH
(9)






A
(10)












A

class Number2
    {
        String[] Str_ = new String[30];
        const string Alphabet = "";

        public void Solve()
        {

            for (int i = 0; i < 10; i++)
            {
                if (i == 0)
                {
                    Str_[i] += Alphabet[i];
                }
                else
                {
                    Str_[i] = Str_[i - 1] + Str_[i - 1] + Alphabet[i];
                }
                Console.WriteLine("({0}) {1}", i + 1, Str_[i]);
                if (Str_[i].Length >= 256)
                {
                    Console.WriteLine("{0}",Str_[i][256 - 1]);
                }
            }
        }
    }