\begin{gathered}10+\Big(3-x\Big)^3=x^2*\Big(9-x\Big)-17Formyla\;:boxed{\;\;\Big(a-b\Big)^3=a^3-3*a^2*b+3*a*b^2-b^3\;\;\;}10+3^3-3*3^2*x+3*3*x^2-x^3=9x^2-x^3-1710+27-27x+9x^2-x^3=9x^2-x^3-1727x=54boxed{\;\;\Big{x=2}\;\;}\\\end{
10+(3-х)3=х2(9-х)-17
(3-х)3-х2*(9-х)=-17-10
27-27х=-27
-27х=-27-27
х=2
