f'(x)= 2x(3x²-2) · 6x³
f'(1)= 12
f(1)= 1
f'(1)+f(1)= 12+1= 13
f'(x) = (x²(3x²-2))' = (3x⁴ - 2x²)' = 12x³ - 4x
f '(1) + f(1) = 12*1³ - 4*1 + 1²(3*1²-2) = 12 - 4 + 3 - 2 = 9
