Хто 1) 1-cos(270°+α)sin(180°-α) 2) cos(π+α)cos(α+2π)+sin²(α-∛π÷2) - вопрос №977938711270180222 от mybrainishere11 03.05.2021 18:52

Question

Алгебра: Хто 1) 1-cos(270°+α)sin(180°-α) 2) cos(π+α)cos(α+2π)+sin²(α-∛π÷2)

mybrainishere11 · Answer

1) 1 - Cos(270⁰ + α )Sin(180⁰ - α ) = 1 - Sinα * Sinα = 1 - Sin²α = Cos²α2) Cos(π + α)Cos(α + 2π) + Sin²(α - 3π/2) = - Cosα * Cosα + Cos²α == - Cos²α + Cos²α = 0...