task/29414459 упростите Выражение
1. (sin3x+sinx) / (cos3x +cosx) =2sin2xcosx / 2cos2xcosx =sin2x/cos2x= tg2x .
2. (ctg²α*sin²α -ctg²α) / (tg²α*cos²α -tg²α) =ctg²α(sin²α -1) / tg²α(cos²α -1) =
ctg²α*(-cos²α) / tg²α(-sin²α) = ctg⁶α .
