2a(a^4-16)=0
a=0 или a^4=32 => a=2 или a=-2
y^2(y+1)+9(y+1)=0
(y^2+9)(y+1)=0
y=-1
2aˇ5-32a=2a(aˇ4-16)=2a(aˇ4-2ˇ4)=2a(aˇ2+2ˇ2)(aˇ2-2ˇ2)=
=2a(aˇ2+4)(a+2)(a-2)=0
1)a=0, a=-2,a=2
2)aˇ2+4=0, a∉R
y³+y²+9y+9=y²(y+1)+9(y+1)=(y+1)(y²+1)=0
1)y=-1
2)y²+1=0, y∉R
