(7-2x)(49+14x4x^2)+2x(2x-5)(2x+5)=43 100(0,2x+1)(0,04x^2-0,2x+1)=5x(0,16x^2-4) - вопрос №867694472491442225254310002100420215016 от tflash191 03.06.2020 12:35

Question

Алгебра: (7-2x)(49+14x4x^2)+2x(2x-5)(2x+5)=43 100(0,2x+1)(0,04x^2-0,2x+1)=5x(0,16x^2-4)

tflash191 · Answer

(7-2x)(49+14x+4x^2)+2x(2x-5)(2x+5)=43343-8x³+8x³-50x=4350x=343-4350x=300x=300:50x=6100(0,2x+1)(0,04x^2-0,2x+1)=5x(0,16x^2-4)100(0,008x³+1)=5x(0,16x²-4)0,8x³+100-0,8x³+20x=020x=-100x=-100:20x=-5...