)1) (x-y)5=x+y x^2-y^2=100 2)x^2+y^2=31 y^2-4x^2=1 - вопрос №86089261522100222312421 от Princesska88 05.01.2022 06:22

Question

Алгебра: )1) (x-y)5=x+y x^2-y^2=100 2)x^2+y^2=31 y^2-4x^2=1

Princesska88 · Answer

(x-y)5=x+yx²-y²=1005х-5у=х+уx²-y²=1005х-5у-х-у=0x²-y²=1004х-6у=0x²-y²=1004х=6уx²-y²=100х=1,5у(1,5у)²-у²=100х=1,5у2,25у²-у²=100х=1,5у1,25у²=100х=1,5уу²=80х=1,5уу=±√80х=1,5уу=+-4√5х=6√5у=4√5х= -6√5у= -4√5ответ: (6√5;4√5); (-6√5;-4√5)x²+y²=31. *(-1)y²-4x²=1-х²-у²= -31у²-4х²=1-5х²= -30x²+y²=31х²=6x²+y²=31х=±√6у²=25х=±√6у=±5х=√6у=5х= -√6у= -5х=√6у= -5 ответ:(√6;5);(-√6;5);(√6;-5)...