Разложите на множители: 16x^2-81y^2 0.01m^2-2.25n^2 - вопрос №85902401628120012225292064249210 от darkdemonsown3mz 05.04.2022 07:20

Question

Алгебра: Разложите на множители: 16x^2-81y^2 0.01m^2-2.25n^2 9a^2-0.64b^2 49x^2-100 0.36x^2-289 81a^2-2.56 9a^4-0.64b^6

darkdemonsown3mz · Answer

16x^2-81y^2=(4х-9у)(4х+9у)0.01m^2-2.25n^2=(0.1m-1.5n)(0.1m+1.5n)9a^2-0.64b^2=(9a-0.8b)(9a+0.8b)49x^2-100=(7x-10)(7x+10)0.36x^2-289=(0.6x-17)(0.6x+17)81a^2-2.56=(9a-1.6)(9a+1.6)9a^4-0.64b^6=(3a²-0.8b³)(3a²+0.8b³)...