Решите уравнение (x-2)^2+48=(2-3x)^2

(x - 2)² + 48 = (2 - 3x)²
(x - 2)² - (2 - 3x)² = -48
(x - 2 + 2 - 3x)(x - 2 - 2 + 3x) = -48
(-2x)(4x - 4) = -48
-8x² + 8x + 48 = 0
x² - x - 6 = 0              D = b²-4ac = 1+24 = 25

x₁ = (1-5)/2 = -2
x₂ = (1+5)/2 = 3

ответ: {-2; 3}