Решить log4log3log2 x =1/2 log(x-1)=log4(x^2-x-16) - вопрос №83105594321214216 от makslitovchenk 14.06.2021 08:03

Question

Алгебра: Решить log4log3log2 x =1/2 log(x-1)=log4(x^2-x-16)

makslitovchenk · Answer

1)  4^(1/2) = 2 = log3(log2(x))3^2 = 9 = log2(x)2^9 = 512 = xответ: 5122)   log4 x - 1/2log4 x = 1/4log4 x - log4 x^1/2 = 1/4log4 (x/x^1/2)=1/4log4 x^1/2=1/44^1/4=x^1/22^(2*1/4)=x^1/22^1/2=x^1/2x=2...