2log(1/3)6 - 1/2log(1/3)400 + 3log(1/3) ³√45 - вопрос №70666062136121340031345 от Dybnii48ĵĝ 05.12.2020 08:10

Question

Алгебра: 2log(1/3)6 - 1/2log(1/3)400 + 3log(1/3) ³√45

Dybnii48ĵĝ · Answer

2log(1/3)6 - 1/2log(1/3)400 + 3log(1/3) ³√45 =
= log (1/3)6^2 - log(1/3)√(400) + log(1/3)(∛45)^3 =
= log(1/3) 36 - log (1/3) 20 + log(1/3) 45 =
= log (1/3) (36/20) + log (1/3) 45 =
= log (1/3) (9/5) + log (1/3) 45 =
= log (1/3) ((9*45)/5) =
= log (1/3) 81 =
= log 3^(-1) 3^4 =
= - log 3 3^4 = - 4