Решить 1)3cos^2 x-2,5sin2x-2sin^2 x=0 2) корень3sinx-cosx=2

3cos²x - 2,5sin2x - 2sin²x = 0
Разложим sin2x.
3cos²x - 5sinxcosx - 2sin²x = 0
Разделим на cos²x (cosx ≠ 0).
3 - 5tgx - 2tg² = 0
2tg²x + 5tgx - 3 = 0
Пусть t = tgx.
2t² + 5t - 3 = 0
D = 25 + 3•4•2 = 49 = 7².
t = (-5 + 7)/4 = 1/2
t = (-5 - 7)/4 = -12/4 = -3
Обратная замена:
tgx = 1/2
x = arctg(1/2) + πn, n ∈ Z
tgx = -3
x = arctg(-3) + πn, n ∈ Z.

2) √3sinx - cosx = 2

√3/2sinx - 1/2cosx = 1
cos(π/6)sinx - sin(π/6)cosx = 1
По формуле синуса разности аргументов:
sin(x - π/6) = 1
x - π/6 = π/2 + 2πn, n ∈ Z
x = π/2 + π/6 + 2πn, n ∈ Z
x = 2π/3 + 2πn, n ∈ Z.