Решите будьте добры 1) lim x-> -1 x^3+x^2-x-1/x^2+3x+2 2)lim x-> 1/3 6x^2-5x+1/27x^3-1 3)lim x-> 1,5 8x^3-36x^2+54x-27/4x^2-12x+9

1) lim x->-1 x^3+x^2-x-1/x^2+3x+2 = lim x->-1 (x²-1)/(x+2) = 0/-1=0
(x²(x+1)-(x+1))/(x+1)(x+2)=((x²-1)(x+1))/(x+1)(x+2)=(x²-1)/(x+2)
2)lim x->1/3 6x^2-5x+1/27x^3-1 = lim x->1/3 (2x-1)/(9x²+3x+1) = (2*1/3-1)/(9*1/9 + 3*1/3+1)= (2/3-1)/(1+1+1)=-1/9
D=25-24=1
x12=(5+-1)/12=1/2 1/3
(3x-1)(2x-1)/(3x-1)(9x²+3x+1)=(2x-1)/(9x²+3x+1)
3)lim x->1,5 8x^3-36x^2+54x-27/4x^2-12x+9= limx->1.5 (2x-3)= 2*1.5-3=0
8x^3-36x^2+54x-27/4x^2-12x+9 = (2x-3)³/(2x-3)²=2x-3