Решите 1. (2/3)^x 1 1/2 2. 9^2x≤1/3 3. (1/7)^x^2-9≤1 - вопрос №635747412311229213317291442180 от weloyda 20.09.2020 06:25

Question

Алгебра: Решите 1. (2/3)^x 1 1/2 2. 9^2x≤1/3 3. (1/7)^x^2-9≤1 4. 4^x+2^x+1-80 0 5. (1/3)^t 1/27

weloyda · Answer

1) (2/3)^x 11/2(2/3)^x 3/2(2/3)^x (2/3)^(-1)т к 2/3 1то х (-1)2) 9^2x =1/33^4x =3^(-1)4x =-1x =-1/4...

Решите 1. (2/3)^x> 1 1/2 2. 9^2x≤1/3 3. (1/7)^x^2-9≤1 4. 4^x+2^x+1-80< 0 5. (1/3)^t< 1/27