2/x^2+12x+36-12/36-x^2=1/x-6 решите !

2/(x+6)^2 -12/(6 -x)(6+x) =1/(x -6)

2/(x+6)^2 +12/(x -6)(6+x) =1/(x -6)

(2(x -6) +12(x+6)) /(x -6)(x+6)^2 =1/(x -6)

(2x -12 +12x +72) /(x -6)(x+6)^2 -1/(x -6) =0

((14x +60) -(x +6)^2) /(x-6)(x+6)^2 =0

14x +60 -x^2 -12x -36 =0, *(-1)

x^2 -2x -24 =0

D =4 +4*24 =100 =10^2

x1 =(2 -10)/2 = -4

x2 =(2+10)/2 =6

ответ: x1 = -4; x =6