Решите уравнения. 1)(х-5)(х+1)=0 2)(2х-8)(4x+3)=0 за ранее !

1) (x - 5)(x + 1) = 0 
x = 5
x = - 1

2) (2x - 8)(4x + 3) = 0 
x = 4;
x = - 0,75 

N 1
( X - 5 )( X + 1 ) = 0
X - 5 = 0
X = 5
X + 1 = 0
X = - 1
ответ ( - 1 ) ; 5
N 2
( 2x - 8 )( 4x + 3 ) = 0
2x - 8 = 0
2x = 8
X = 4
4x + 3 = 0
4x = - 3
X = - 0,75
ответ ( - 0,75 ) ; 4