1) (2/3)^x * (9/8)^x=27/64 2)10^x - 5^(x-1) *2^(x-2)=950 - вопрос №5804276123982764210512295035525 от silva78 27.03.2022 00:07

Question

Алгебра: 1) (2/3)^x * (9/8)^x=27/64 2)10^x - 5^(x-1) *2^(x-2)=950 3)5^x+5^(x+2) +5^(x+4)=651

silva78 · Answer

10ˣ-5ˣ⁻¹*2ˣ⁻²=9502ˣ*5ˣ-5ˣ*5⁻¹*2ˣ*2⁻²=9502ˣ*5ˣ(1-5⁻¹*2⁻²)=95010ˣ*(19/20)=95010ˣ=950*20/1910ˣ=100010ˣ=10³x=35ˣ+5ˣ⁺²+5ˣ⁺⁴=6515ˣ+5ˣ*5²+5ˣ*5⁴=6515ˣ(1+25+625)=6515ˣ*651=6515ˣ=651:6515ˣ=15ˣ=5⁰x=0...