Вычислите: 〖3^2〗^ 3^5)²)/27³; б)32²/((2^4 )^3•2^6 - вопрос №561130932352732243265410232 от Sofya768Miller 01.01.2023 02:38

Question

Алгебра: Вычислите: 〖3^2〗^ 3^5)²)/27³; б)32²/((2^4 )^3•2^6 ).; в)(5^4•10³)/(2^3•〖25〗^2 )

Sofya768Miller · Answer

A) (3² * 3⁵)²/27³ = (3²⁺⁵)²/(3³)³ = 3¹⁴/3⁹=3¹⁴⁻⁹=3⁵=243

б) 32²/[(2⁴)³ * 2⁶]=[(2⁵)²] / [2¹² * 2⁶] = 2¹⁰ / 2¹²⁺⁶=2¹⁰ / 2¹⁸ = 1/2⁸ = 1/256

в) (5⁴ * 10³) / (2³ * 25²) = (5⁴ * (2*5)³) / (2³ * (5²)²) =
=(5⁴ * 2³ * 5³) / (2³ * 5⁴) = (5⁴⁺³ * 2³) / (2³ * 5⁴) =
= (5⁷ * 2³) / (2³ * 5⁴) = 5⁷⁻⁴=5³=125