1)29х+48 =3(7х+3)-1 2)-6(х-6)-8= 34-4x 3)-93 4(2x-6)+3 - вопрос №553069812948373126683443934263 от nikvet 28.12.2020 00:34

Question

Алгебра: 1)29х+48 =3(7х+3)-1 2)-6(х-6)-8= 34-4x 3)-93 4(2x-6)+3 !

nikvet · Answer

1)29х+48 =3(7х+3)-129х+48 =21х+9-129х-21х =9-1-488х =-40х =-40:8х =-52)-6(х-6)-8= 34-4х-6х+36-8= 34-4х-6х+4х= 34-36+8-2х= 6х =6:(-2)х =-33)-93 4(2х-6)+3-93 8х-24+3-8х -24+3+93-8х 72х 72:(-8)х -9...

1)29х+48< =3(7х+3)-1 2)-6(х-6)-8=> 34-4x 3)-93> 4(2x-6)+3 !