Решить уравнение: a)√x^2-3x=x+3 b)6/x + 6/x+1 =5 - вопрос №55007052336615 от kanamariya021 23.03.2022 22:29

Question

Алгебра: Решить уравнение: a)√x^2-3x=x+3 b)6/x + 6/x+1 =5

kanamariya021 · Answer

√x^2 - 3x = x + 3x^2 - 3x = ( x + 3)^2x^2 - 3x = x^2 + 6x + 9x^2 - x^2 - 3x - 6x = 9- 9x = 9x = - 16/x + 6/x + 1 = 56( x + 1) + 6x = 5x(x + 1)6x + 6 + 6x = 5x^2 + 5x12x - 5x - 5x^2 + 6 = 0- 5x^2 + 7x + 6 = 05x^2 - 7x - 6 = 0D = b^2 - 4ac = 49 + 120 = 169 = 13^2x1 = ( 7 + 13) / 10 = 2x2 = ( 7 - 13) / 10 = - 0,6...