Решите уравнение а)3(1-2х)-5(3-х)-6(3х-4)=83 б)23-3(b+1)+5(6b-7)-7(3b-1)=0 в)х(2х+3)-5(х^2-3х)=3х(7-х) г)2м+м(3-(м+1))=м(2-м)+12 б)7+3(-к-3(к+5))=5(7-2к)+к !

a)3(1-2x)-5(3-x)-6(3x-4)=83

3-6x-15+5x-18x+24=83

-19x+12=83

-19x=83-12

-19x=71

x=71/(-19)

x=-3 14/19

b)23-3(B+1)+5(6B-7)-7(3B-1)=0

23-3B+3+30B-35-21B+7=0

6B-8=0

6B=8

B=8/6

B=1 1/3

в)2m+m(3-(m+1))=m(2-m)+12

2m+3m-m^2-m=2m-m^2+12

2m=12

m=6

Б)7+3(-k-3(k+5))=5(7-2k)+k

7-3k+9k-45=35-10k+k

15k=73

k=73/15

k=4 13/15