1)5x^2-18x+16 2)3x^2-11x-14 3)x^2-x-1 решить - вопрос №483959015218162321114321 от Priveee 12.11.2020 05:56

Question

Алгебра: 1)5x^2-18x+16 2)3x^2-11x-14 3)x^2-x-1 решить через дискриминант

Priveee · Answer

1) 5x² - 18x + 16 = 0D = b² - 4ac = 324 - 4 × 5 × 16 = 324 - 320 = 4 = 2²x1 = ( 18 + 2) / 10 = 2x2 = ( 18 - 2) / 10 = 1,62) 3x² - 11x - 14 = 0D = b² -4ac = 121 - 4×3×(-14) = 121 + 168 = 289 = 17²x1 = ( 11 + 17) / 6 = 28/6 = 4 4/6 = 4 2/3x2 = ( 11 - 17) / 6 = - 13) x² - x - 1 = 0D = b² - 4ac = 1 - 4×(- 1) = 1 + 4 = 5x1 = ( 1 + √5)/2x2 = ( 1 - √5) / 2...