А)(5x-3)+(7x-4)=8-(15-11x) б)(4х++11)=7+(13-4х) - вопрос №439678453748151141171347456832 от mdotsenko 22.08.2022 12:18

Question

Алгебра: А)(5x-3)+(7x-4)=8-(15-11x) б)(4х++11)=7+(13-4х) в)(7--4х)+(5х+6)=8 г)(3-2х)+(4-3х)+(5-5х)=12+7х

mdotsenko · Answer

А)(5х-3)+(7х-4)=8-(15-11х)5х-3+7х-4=8-15+11х5х+7х-11х=8-15+3+4х=0б)(4х+3)-(10х+11)=7+(13-4х)4х+3-10х-11=7+13-4х4х-10х+4х=20-3+11-2х=28х=28/-2х=-14в)(7-5х)-(8-4х)+(5х+6)=87-5х-8+4х+5х+6=84х=8-54х=3х=3/4х=0,75г)(3-2х)+(4-3х)+(5-5х)=12+7х3-2х+4-3х+5-5х=12+7х-10х-7х=12-12-17х=0х=0...