Решить уравнение 2cos(-x/2+п/4)=-2 и 2sin(п/3-x/4)=√3

1) 2cos (-0.5x + π/4) = -2
cos (-0.5x + π/4) = -1
cos (0.5x - π/4) = -1
0.5x - π/4 = π + 2πn
0.5x = π + π/4 + 2πn
0.5x = 5π/4 + 2πn
x = 10π/4 +4πn

2) 2sin (π/3 - x/4) = √3
sin (π/3 - x/4) = 0.5√3
sin (-π/3 + x/4) = -0.5√3
a) (-π/3 + x/4) = -π/3 + 2πn              b) (-π/3 + x/4) = -2π/3 + 2πn
        x/4 = 2πn                                           x/4 = -π/3 + 2πn
       x1 = 8πn  n∈Z                                      x2 = -4π/3 + 8πn      n∈Z