(x+3)/x=(2x+10)/(x-3)(x^2-9-2x^2-10x)/x(x-3) =0Cистема:-x^2-10x-9=0 (*(-1))x^2+10x+9=0x1=-1x2=-9
x(x-3)=/=0x=/=0x=/=3
ответ:x=-9;x=-1;