|x^2+y^2=20 |x^2+y^2=20 |x^2+(2-3x)^2=20 |x^2+4-12x+9x^2=20
|3x+y=2 |y=2-3x |y=2-3x |y=2-3x
10x^2-12x-16=0 5x^2-6x-8=0 x1=-0.8
x2=2
Подставим:
1)y=2-3*(-0.8)=2-2.4=-0.4
2)y=2-3*(2)=2-6=-4
ответ:x1=-0.8 x2=2 y1=-0.4 y2=-4
