x³+3x² = 4x+12;
x²(x + 3) = 4(x + 3);
x²(x + 3) - 4(x + 3) = 0;
(x + 3)(x² - 4) = 0;
(x + 3)(x - 2)(x + 2) = 0;
x₁ = -3; x₂ = 2; x₃ = -2.
ответ: -3; ±2.
х^3 + 3x^2 - 4x - 12 = 0
x^2(x+3) - 4(x+3) = 0
(x+3)(x^2 - 4) = 0
(x+3)(x-2)(x+2) = 0
x=-3
x=2
x=-2
Объяснение:
